| 1 | /* $Id$ $Revision$ */ | 
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| 2 | /* vim:set shiftwidth=4 ts=8: */ | 
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| 3 |  | 
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| 4 | /************************************************************************* | 
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| 5 | * Copyright (c) 2011 AT&T Intellectual Property | 
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| 6 | * All rights reserved. This program and the accompanying materials | 
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| 7 | * are made available under the terms of the Eclipse Public License v1.0 | 
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| 8 | * which accompanies this distribution, and is available at | 
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| 9 | * http://www.eclipse.org/legal/epl-v10.html | 
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| 10 | * | 
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| 11 | * Contributors: See CVS logs. Details at http://www.graphviz.org/ | 
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| 12 | *************************************************************************/ | 
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| 13 |  | 
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| 14 |  | 
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| 15 | #include "config.h" | 
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| 16 | #include <math.h> | 
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| 17 | #include "solvers.h" | 
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| 18 |  | 
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| 19 | #ifdef DMALLOC | 
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| 20 | #include "dmalloc.h" | 
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| 21 | #endif | 
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| 22 |  | 
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| 23 | #ifndef HAVE_CBRT | 
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| 24 | #define cbrt(x) ((x < 0) ? (-1*pow(-x, 1.0/3.0)) : pow (x, 1.0/3.0)) | 
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| 25 | #endif | 
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| 26 | #ifndef M_PI | 
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| 27 | #define M_PI 3.14159265358979323846 | 
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| 28 | #endif | 
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| 29 |  | 
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| 30 | #define EPS 1E-7 | 
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| 31 | #define AEQ0(x) (((x) < EPS) && ((x) > -EPS)) | 
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| 32 |  | 
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| 33 | int solve3(double *coeff, double *roots) | 
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| 34 | { | 
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| 35 | double a, b, c, d; | 
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| 36 | int rootn, i; | 
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| 37 | double p, q, disc, b_over_3a, c_over_a, d_over_a; | 
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| 38 | double r, theta, temp, alpha, beta; | 
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| 39 |  | 
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| 40 | a = coeff[3], b = coeff[2], c = coeff[1], d = coeff[0]; | 
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| 41 | if (AEQ0(a)) | 
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| 42 | return solve2(coeff, roots); | 
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| 43 | b_over_3a = b / (3 * a); | 
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| 44 | c_over_a = c / a; | 
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| 45 | d_over_a = d / a; | 
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| 46 |  | 
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| 47 | p = b_over_3a * b_over_3a; | 
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| 48 | q = 2 * b_over_3a * p - b_over_3a * c_over_a + d_over_a; | 
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| 49 | p = c_over_a / 3 - p; | 
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| 50 | disc = q * q + 4 * p * p * p; | 
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| 51 |  | 
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| 52 | if (disc < 0) { | 
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| 53 | r = .5 * sqrt(-disc + q * q); | 
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| 54 | theta = atan2(sqrt(-disc), -q); | 
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| 55 | temp = 2 * cbrt(r); | 
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| 56 | roots[0] = temp * cos(theta / 3); | 
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| 57 | roots[1] = temp * cos((theta + M_PI + M_PI) / 3); | 
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| 58 | roots[2] = temp * cos((theta - M_PI - M_PI) / 3); | 
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| 59 | rootn = 3; | 
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| 60 | } else { | 
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| 61 | alpha = .5 * (sqrt(disc) - q); | 
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| 62 | beta = -q - alpha; | 
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| 63 | roots[0] = cbrt(alpha) + cbrt(beta); | 
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| 64 | if (disc > 0) | 
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| 65 | rootn = 1; | 
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| 66 | else | 
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| 67 | roots[1] = roots[2] = -.5 * roots[0], rootn = 3; | 
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| 68 | } | 
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| 69 |  | 
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| 70 | for (i = 0; i < rootn; i++) | 
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| 71 | roots[i] -= b_over_3a; | 
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| 72 |  | 
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| 73 | return rootn; | 
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| 74 | } | 
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| 75 |  | 
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| 76 | int solve2(double *coeff, double *roots) | 
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| 77 | { | 
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| 78 | double a, b, c; | 
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| 79 | double disc, b_over_2a, c_over_a; | 
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| 80 |  | 
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| 81 | a = coeff[2], b = coeff[1], c = coeff[0]; | 
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| 82 | if (AEQ0(a)) | 
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| 83 | return solve1(coeff, roots); | 
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| 84 | b_over_2a = b / (2 * a); | 
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| 85 | c_over_a = c / a; | 
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| 86 |  | 
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| 87 | disc = b_over_2a * b_over_2a - c_over_a; | 
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| 88 | if (disc < 0) | 
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| 89 | return 0; | 
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| 90 | else if (disc == 0) { | 
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| 91 | roots[0] = -b_over_2a; | 
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| 92 | return 1; | 
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| 93 | } else { | 
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| 94 | roots[0] = -b_over_2a + sqrt(disc); | 
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| 95 | roots[1] = -2 * b_over_2a - roots[0]; | 
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| 96 | return 2; | 
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| 97 | } | 
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| 98 | } | 
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| 99 |  | 
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| 100 | int solve1(double *coeff, double *roots) | 
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| 101 | { | 
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| 102 | double a, b; | 
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| 103 |  | 
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| 104 | a = coeff[1], b = coeff[0]; | 
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| 105 | if (AEQ0(a)) { | 
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| 106 | if (AEQ0(b)) | 
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| 107 | return 4; | 
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| 108 | else | 
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| 109 | return 0; | 
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| 110 | } | 
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| 111 | roots[0] = -b / a; | 
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| 112 | return 1; | 
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| 113 | } | 
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| 114 |  | 
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