| 1 | #include <ogdf/graphalg/MaxAdjOrdering.h> |
| 2 | #include <ogdf/basic/graph_generators.h> |
| 3 | |
| 4 | #include <testing.h> |
| 5 | |
| 6 | go_bandit([](){ |
| 7 | describe("Maximum Adjacency Orderings" , [](){ |
| 8 | it("should calculate exactly all MAOs" , [](){ |
| 9 | for (int N = 4; N <= 8; N++){ |
| 10 | std::cout << " " << "Busy with graphs that have " << N << " nodes." << std::endl; |
| 11 | Graph P; |
| 12 | emptyGraph(P, N); |
| 13 | MaxAdjOrdering perms; |
| 14 | ListPure<ListPure<node>> allPerms; |
| 15 | perms.calcAll(&P,&allPerms); |
| 16 | |
| 17 | for (int i = 1; i < 10; i++){ |
| 18 | Graph G; |
| 19 | randomSimpleGraph(G,N,1*N); |
| 20 | |
| 21 | //make an instance for the MAOs |
| 22 | MaxAdjOrdering m; |
| 23 | |
| 24 | //make structures for saving all MAOs of G |
| 25 | ListPure<ListPure<node>> MAOs; |
| 26 | |
| 27 | //calculate them |
| 28 | m.calcAll(&G,&MAOs); |
| 29 | |
| 30 | AssertThat(m.testIfAllMAOs(&G,&MAOs,&allPerms), IsTrue()); |
| 31 | } |
| 32 | } |
| 33 | }); |
| 34 | it("should calculate MAOs with correct lex-bfs tie breaking" , [](){ |
| 35 | for (int N = 10; N <= 20; N++){ |
| 36 | std::cout << " " << "Busy with graphs that have " << N << " nodes." << std::endl; |
| 37 | |
| 38 | for (int i = 1; i < 10; i++){ |
| 39 | Graph G; |
| 40 | randomSimpleGraph(G, N, (N*(N-4))/2); |
| 41 | |
| 42 | //make an instance for the MAOs |
| 43 | MaxAdjOrdering m; |
| 44 | |
| 45 | //make structures for saving all MAOs of G |
| 46 | ListPure<node> MAO; |
| 47 | |
| 48 | //calculate them |
| 49 | m.calcBfs(&G,&MAO); |
| 50 | |
| 51 | AssertThat(m.testIfMAO(&G,&MAO), IsTrue()); |
| 52 | AssertThat(m.testIfMAOBfs(&G,&MAO), IsTrue()); |
| 53 | } |
| 54 | } |
| 55 | }); |
| 56 | }); |
| 57 | }); |
| 58 | |